48x^2+60x+28x=0

Solution for 48x^2+60x+28x=0 equation:

48x^2+60x+28x=0

We add all the numbers together, and all the variables

48x^2+88x=0

a = 48; b = 88; c = 0;
Δ = b2-4ac
Δ = 882-4·48·0
Δ = 7744
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7744}=88$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(88)-88}{2*48}=\frac{-176}{96}
=-1+5/6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(88)+88}{2*48}=\frac{0}{96}
=0
$